AP EAMCET20228 Jul 2022Morning ShiftMathematicsProbabilityActual
A box contains 6 bottles of V ₁ drink, 3 bottles of V ₂ drink and 4 bottles of V ₃ drink. If three bottles are drawn at random, then the probability that the three are not of the same variety is
Options
- A632 713
- B752 833
- C833 858
- D261 286
Correct answer
D. 261 286
Step-by-step solution
P[All of three bottles are of same variety] = 6_ C ₃ +3_ C ₃ +4_ C ₃ 13_ C ₃ = 6.5 4 3.2 .1 +1+4 13 10.11 3.2 .1 P(E)= 25 26 11 P [ All of three bottles are not of same variety] =1- 25 286 = 261 286