The probability of getting a sum 9 when two dice are thrown is

Step-by-step solution

When two dice are rolled together, then total outcomes are 36 and sample space is aligned & [(1,1),(1,2),(1,3),(1,4),(1,5)(1,6), & (2,1),(2,2),(2,3),(2,4),(2,5),(2,6), & (3,1),(3,2),(3,3),(3,4),(3,5),(3,6), & (4,1),(4,2),(4,3),(4,4),(4,5),(4,6), & (5,1),(5,2),(5,3),(5,4),(5,5),(5,6), & (6,1),(6,2),(6,3),(6,4),(6,5),(6,6)] aligned So, pairs with sum 9 are (3,6)(4,5),(5,4),(6,3) i.e total 4 pairs. Total outcomes =36 Favourable outcomes =4 Probability of getting the sum of 9 = 4 36 = 1 9