For a Poisson distribution, if mean =l , variance =m and l+m=8 , then e^4[1-P(X>2)]=

Step-by-step solution

For Poisson distribution, mean = variance l=m=4 So, e^4[1-P(X>2)] aligned & =e^4[P 2] & =e^4[P(X=0)+P(X=1)+P(X=2)]] & =e^4 [ e⁻⁴ 4^0 0 ! + e⁻⁴ 4^1 1 ! + e⁻⁴ 4^2 2 ! ] . & =e^4 e⁻⁴(1+4+8)=13 aligned