AP EAMCET20224 Jul 2022Evening ShiftMathematicsProbabilityActual
A manager decides to distribute Rs . 20000 between two employees X and Y . He knows X deserves more than Y , but does not know how much more. So, he decides to arbitrarily break Rs . 20000 in to two parts and gives X the bigger part. Then, the chance that X gets twice as much as Y or more is
Options
- A2 5
- B1 2
- C1 3
- D2 3
Correct answer
D. 2 3
Step-by-step solution
Given, X gets the bigger part than Y So, the bigger part could be any number from 10000 to 20000 . Now, if the bigger part is to be at least twice as much as the smaller part, we have X ≥ 2 Y ⇒ X ≥ 2 20000 - X ⇒ X ≥ 40000 3 So, the probability is equal to 20000 - 40000 / 3 20000 - 10000 = 2 3 Hence the answer is 2 3