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AP EAMCET202124 Aug 2021Evening ShiftMathematicsProbabilityActual

For a binomial distribution B(n, p) mean =200 , standard deviation =10 , then n^2+ 1 p^2 + 1 q^2 is equal to

Options

  1. A160004
  2. B160006
  3. C160008
  4. D160002

Correct answer

C. 160008

Step-by-step solution

In binomial distribution mean =n p and standard deviation = n p q 200=n p and 10= n p q 200=n p ...(i) 100=n p q ...(ii) From Eqs. (i) and (ii), we get q= 1 2 , n=400 and p= 1 2 n^2+ 1 p^2 + 1 q^2 (400)^2+(2)^2+(2)^2=160000+4+4=160008

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