The probability for a contractor to get a road contract is 2 9 and to get a building contract is 5 9 , if the probability to get both the contract is 1 6 , then what is the probability to get neither of these two contracts?

Step-by-step solution

Let A be the event of getting a road contract and B be the event of getting a building contract. P(A)= 2 9 , P(B)= 5 9 P(A B)= 1 6 P(A B)=P(A)+P(B)-P(A B) aligned & = 2 9 + 5 9 - 1 6 & = 7 9 - 1 6 = 14-3 18 = 11 18 aligned P ((A B)^ )=1-P(A B)=1- 11 18 = 7 18 Hence, the probability to get neither of these two contracts is 7 / 18 .