AP EAMCET202120 Aug 2021Evening ShiftMathematicsProbabilityActual
The range of a random variable X is 1 , 2 , 3 … . . . and P ( X = x ) = c x x ! , for x = 1 , 2 , 3 , … … Then the value of C is
Options
- A0
- B1
- Cln ( 2 )   ( where ln denotes the natural log )
- Dln ( 3 )   ( where ln denotes the natural log )
Correct answer
C. ln ( 2 )   ( where ln denotes the natural log )
Step-by-step solution
Given: P X = x = c x x ! ∵   ∑ P X = 1 ⇒   c + c 2 2 ! + c 3 3 ! + . . . . . = 1 ⇒   1 + c + c 2 2 ! + c 3 3 ! + . . . . . .   = 2 ⇒   e c = 2 ⇒   c log e e = log e 2 ⇒ c = ln 2