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AP EAMCET202120 Aug 2021Morning ShiftMathematicsProbabilityActual

One card is selected at random from 27 cards numbered form 1 to 27 . What is the probability that the number on the card is even or divisible by 5 .

Options

  1. A15 27
  2. B16 27
  3. C17 27
  4. D18 27

Correct answer

B. 16 27

Step-by-step solution

Total numbers n S = 27 Even numbers possible to get = 2 , 4 , 6 , 8 , 10 , 12 , 14 , 16 , 18 , 20 , 22 , 24 , 26 ⇒ n E = 13 Number divisible by 5 will be = 5 , 10 , 15 , 20 , 25 ⇒ n 5 = 5 Total possibility of getting even number or divisible by 5 = n E ∩ 5 = 16 therefore, Probability = n E ∩ 5 n S = 16 27

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