AP EAMCET202119 Aug 2021Evening ShiftMathematicsProbabilityActual
A discrete random variable X takes values 10 , 20 , 30 and 40 , with probability 0 . 3 , 0 . 3 , 0 . 2 , 0 . 2 respectively. Then the expected value of X is
Options
- A12
- B22
- C23
- D24
Correct answer
C. 23
Step-by-step solution
Expected value of X is given by ∑ X P ( X ) , where P ( X ) is probability of random variable X . ⇒ ∑ X P ( X ) = 10 × 0 . 3 + 20 × 0 . 3 + 30 × 0 . 2 + 40 × 0 . 2 = 3 + 6 + 6 + 8 = 23