Five different books are to be distributed among four students randomly. The probability that each child get atleast one book is

Step-by-step solution

Total number of ways to distribute five different books among four students randomly is 4^5=2¹⁰=1024 and number of ways to distribute five different book among four students such that each child get atleast one book is 5 ! 1 ! 1 ! 1 ! 2 ! 3 ! 4 !=240 So, required probability is 240 1024 = 2^4 3 5 2¹⁰ = 15 64 Hence, option (2) is correct.