AP EAMCET202021 Sep 2020Evening ShiftMathematicsProbabilityActual
In 3 trials of a binomial distribution, the probability of 2 successes is 9 times the probability of 3 successes. Then the probability of success in each trial is
Options
- A( 1 2 )
- B( 1 3 )
- C( 1 4 )
- D( 1 5 )
Correct answer
C. ( 1 4 )
Step-by-step solution
In a 3 trials of a binomial distribution, the probability of 2 successes (=9 ) probability of 3 successes ( aligned & ^3 C₂ p^2 q=9 ( ^3 C₃ p^3 ) where p+q=1 & 3 p^2 q=9 p^3 q=3 p & p= 1 4 = probability of success in each trial. aligned ) Hence, option (c) is correct.