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AP EAMCET201923 Apr 2019Morning ShiftMathematicsProbabilityActual

A Box (B₁ ) contains 3 blue balls and 6 red balls. Another Box (B₂ ) contains 8 blue balls and ' (n ) ' red balls ((n N) ). A ball selected at random from a box is found to be red. If (p ) is the probability that this red ball drawn is from box (B₂ ), then

Options

  1. A( 1 7 p < 3 5 )
  2. B( 3 5 p < 1 )
  3. C(0 < p 3 5 )
  4. D(0 p 1 7 )

Correct answer

A. ( 1 7 p < 3 5 )

Step-by-step solution

According to given information, the required ( probability = 1 2 n n+8 ( 1 2 n n+8 )+ ( 1 2 6 3+6 ) ) (According to Baye's theorem) (= n n+8 n n+8 + 2 3 = 3 n 3 n+2 n+16 = 3 n 5 n+16 =p (given) ) For minimum value of (p, n ) must be ( l ) (as (n N ) ) So, ( p 3 21 p 1 7 ) For maximum value of (p, n ) So, ( p < 3 5 ) ( 1 7 p < 3 5 ) Hence, option (a) is correct.

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