A random variable (X ) has its range ( -1,0,1 ). If its mean is 0.2 and (P(X=0)=0.2 ), then (P(X=1)= )

Step-by-step solution

According to given information, ( array ccc X=-1 & X=0 & X=1 a & b & c array ) Also, given mean (=0.2 ) ( array ll & -a+c a+b+c = 2 10 (i) and & b a+b+c = 2 10 (ii) array ) Now, ( 1+ c-a a+b+c = 2 10 +1 ) ( a+b+c+c-a a+b+c = 12 10 ) ( b+2 c a+b+c = 12 10 ) ( 2 ( c a+b+c )+ 2 10 = 12 10 ) [by Eq. (ii)] ( 2 P(X=1)= 12 10 - 2 10 =1 ) ( 2 P(X=1)=1 ) ( P(X=1)= 1 2 =0.5 )