Four cards are drawn at random from a pack of playing cards. The probability of getting exactly two cards from the same suit and the remaining two cards from two different suits is

Step-by-step solution

We have 52 pack of cards. 52  cards → Club → 13 Diamond → 13 Heart → 13 Spades → 13 Now, for the favourable case we will select any suit and pick two cards from that, and then we will select another suit from the remaining 3 suits and pick two cards. Favourable ways = C 1 4 × C 2 13 × C 2 3 × C 1 13 × C 1 13 . Total ways = C 4 52 . Required probability = C 1 4 × C 2 13 × C 2 3 × C 1 13 × C 1 13 C 4 52 = 4 × 13 × 12 2 × 3 &#215