AP EAMCET201824 Apr 2018Morning ShiftMathematicsProbabilityActual
Given that the probability of a man hitting a target with a gun is 1 3 . If he fires 8 times, then the probability of his hitting the target atleast twice is
Options
- A5 ( 2 3 )^8
- B1-5 ( 2 3 )^8
- C( 2 3 )^8
- D( 3 8 )^4
Correct answer
B. 1-5 ( 2 3 )^8
Step-by-step solution
Probability to hit the target = 1 3 Probability to not hit the target =1- 1 3 = 2 3 Probability to hit the target atleast twice is aligned & =P(2)+P(3)+P(4)+ +P(8) & =1-[P(0)+P(1)] & =1- [ ( 2 3 )^8+ ^8 C₁ ( 2 3 )^7 1 3 ] & =1- ( 2 3 )^7 [ 2 3 +8 1 3 ] & =1- ( 2 3 )^7 10 3 =1-5 ( 2 3 )^8 aligned