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AP EAMCET201823 Apr 2018Evening ShiftMathematicsProbabilityActual

A problem is given to 3 students A, B and C whose chances of solving it are 1 2 , 1 3 and 1 4 respectively. Then, the probability of the problem being solved by exactly one of them, if all the three try independently, is

Options

  1. A3 4
  2. B11 24
  3. C23 24
  4. D1 4

Correct answer

B. 11 24

Step-by-step solution

The required probability aligned =P(A) & P( B ) P( C )+P( A ) P(B) P( C )+P( A ) P( B ) P(C) & = ( 1 2 2 3 3 4 )+ ( 1 2 1 3 3 4 )+ ( 1 2 2 3 1 4 ) & = 1 4 + 1 8 + 1 12 = 11 24 aligned

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