If three numbers are drawn at random successively without replacement from a set S= 1,2, 10 , then the probability that the minimum of the chosen numbers is 3 or their maximum is 7 .

Step-by-step solution

Given, set S= 1,2, , 10 Here, three numbers are drawn at random from the given set. So, total possible outcomes, n= ¹⁰ C₃=120 Let A be the event that minimum of chosen number is 3 . n(A)= 4,5,6,7,8,9,10 = ^7 C₂=21 B be the event that maximum at chosen number is 7 . n(B)= 1,2,3,4,5,6 = ^6 C₂=15 So, n(A B)= 4,5,6 = ^3 C₁=3 Hence, required probability aligned & P= n(A)+n(B)-n(A B) n = 21+15-3 120 & P= 11 40 aligned