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AP EAMCET201726 Apr 2017Morning ShiftMathematicsProbabilityActual

If the mean and variance of a binomial variate X are 4 3 , 8 9 respectively, then P(X=2)=

Options

  1. A4 27
  2. B16 81
  3. C8 27
  4. D8 81

Correct answer

C. 8 27

Step-by-step solution

For a binomial variate x, From Eqs. (i) and (i i) , we have q= 2 3 , p= 1 3 and n=4 Now, P(X=2)= ^4 C₂ p^2 q^2 =6 ( 1 3 )^2 ( 2 3 )^2= 24 81 = 8 27

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