AP EAMCET2015MathematicsProbability
The probability distribution of a random variable is given below Then, P(0 < x < 5) is equal to
Options
- A1 10
- B3 10
- C8 10
- D7 10
Correct answer
C. 8 10
Step-by-step solution
As we know, _ i=1 ^8 P (x_i )=1 aligned & 0+K+2 K+2 K+3 K+K^2+2 K^2+7 K^2+K=1 & 9 K+10 K^2=1 & 10 K^2+9 K-1=0 & 10 K^2+10 K-K-1=0 & 10 K(K+1)-1(K+1)=0 & (K+1)(10 K-1)=0 & K=-1, 1 10 aligned As the probability cannot be negative. So K must be greater than 0 . aligned & K= 1 10 & P(0 < x < 5)=P(X=1)+P(X=2) & +P(X=3)+P(X=4) & =K+2 K+2 K+3 K=8 K & = 8 10 aligned