The coagulation of 200 ~mL of a positive colloid took place when 0.73 ~g HCl was added to it without changing the volume much. The flocculation value of HCl for the colloid is

Correct answer: A. 100 : 200 ~mL of the sol required =0.73 ~g HCl =(0.73)/(36.5)=0.02 ~mol=20 mmol 1000 ~mL(1 ~L) of the sol will require =(20)/(200) × 1000=100 mmol Thus, the flocculation value of HCl for the colloid is 100 .

AIIMS 2017

Exam: AIIMS
Year: 2017
Subject: Chemistry
Chapter: Surface Chemistry

AIIMS 2017 · Chemistry · Surface Chemistry

The coagulation of 200 ~mL of a positive colloid took place when...

The coagulation of

200 \mathrm{~mL}

of a positive colloid took place when

0.73 \mathrm{~g} \mathrm{HCl}

was added to it without changing the volume much. The flocculation value of

\mathrm{HCl}

for the colloid is

Options

A $100$
B $36.5$
C $0.365$
D $150$

Correct answer

A. $100$

Step-by-step solution

200 \mathrm{~mL}

of the sol required

=0.73 \mathrm{~g} \mathrm{HCl}

=\frac{0.73}{36.5}=0.02 \mathrm{~mol}=20 \mathrm{mmol}

\therefore \quad 1000 \mathrm{~mL}(1 \mathrm{~L})

of the sol will require

=\frac{20}{200} \times 1000=100 \mathrm{mmol}

Thus, the flocculation value of

\mathrm{HCl}

for the colloid is 100 .

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