AP EAMCET2008MathematicsProbability
If X is a Poisson variate such that P(X=1)=P(X=2) , then P(X=4) is equal to
Options
- A1 2 e^2
- B1 3 e^2
- C2 3 e^2
- D1 e^2
Correct answer
C. 2 3 e^2
Step-by-step solution
Given that, P(X=1)=P(X=2) array rlrl & & e^ - ^1 1 ! & = e^ - ^2 2 ! & & & =2 & & P(X=4) & = e⁻²(2)^4 4 ! & = e⁻² 16 24 = 2 3 e^2 array