AP EAMCET2006MathematicsProbability
Seven balls are drawn simultaneously from bag containing 5 white and 6 green balls. The probability of drawing 3 white and 4 green balls is :
Options
- A7 ¹¹ C₇
- B^5 C₃+ ^6 C₄ ¹¹ C₇
- C^5 C₂ ^6 C₂ ¹¹ C₇
- D^6 C₃ ^5 C₄ ¹¹ C₇
Correct answer
C. ^5 C₂ ^6 C₂ ¹¹ C₇
Step-by-step solution
Number of ways to get 3 white and 4 green balls from 5 white and 6 green balls = ^5 C₃ ^6 C₄= ^5 C₂ ^6 C₂ and total number of ways = ¹¹ C₇ Required probability = n(E) n(S) = ^5 C₂ ^6 C₂ ¹¹ C₇