An unbiased coin is tossed to get 2 points for turning up a head and one point for the tail. If three unbiased coins are tossed simultaneously, then the probability of getting a total of odd number of points is

Step-by-step solution

We are getting a odd number of point, if it will comes (two head, one tail and three tail) P(H)=P(T)= 1 2 Required probability = Probability of getting two heads and one tail + Probability of all three tails aligned & = ^3 C₂ ( 1 2 )^2 ( 1 2 )^1+ ( 1 2 )^3 & =3 ( 1 2 )^3+ ( 1 2 )^3= 3 8 + 1 8 = 1 2 aligned