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AP EAMCET202021 Sep 2020Morning ShiftMathematicsProperties of TrianglesActual

In ( A B C, A=90^ ) and co-ordinates of points (B ) and (C ) are ((2,-4) ) and ((1,5) ). Then the equation of the circumcircle of ( A B C ) is

Options

  1. A(x^2+y^2+3 x+y+18=0 )
  2. B(x^2+y^2-3 x+y-18=0 )
  3. C(x^2+y^2-3 x-y-18=0 )
  4. D(x^2+y^2+3 x-y+18=0 )

Correct answer

C. (x^2+y^2-3 x-y-18=0 )

Step-by-step solution

It is given that in ( A B C, A=90^ ), so equation of circumcircle of ( A B C ), where (B(2,-4) ) and (C(1,5) ) ( B ) and (C ) are end points of diameter of the circumcircle of ( A B C ), so equation of circumcircle is ( array rlrl & (x-2)(x-1)+(y+4)(y-5) =0 & x^2+y^2-3 x-y-18 =0 array ) Hence, option (c) is correct.

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