If 3 dice are thrown, the probability of getting 10 as the sum of the three numbers that appeared on the top faces of the dice is

Step-by-step solution

n(S)=6 6 6=216 aligned & Sum is 10=(1,3,6),(1,4,5),(1,5,4),(1,6,3), & (2,2,6),(2,3,5),(2,4,4),(2,5,3),(2,6,2), & (3,1,6),(3,2,5),(3,3,4),(3,4,3),(3,5,2),(3,6,1) . & (4,1,5),(4,2,4),(4,3,3),(4,2,4),(4,5,1),(5,1,4), & (5,2,3),(5,3,2),(5,4,1),(6,1,3),(6,2,2),(6,3,1) & n(E)=27 . & Probability = n(E) n(S) = 27 215 = 1 8 . aligned