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AP EAMCET202422 May 2024Evening ShiftMathematicsQuadratic EquationActual

The quotient when 3 x^5-4 x^4+5 x^3-3 x^2+6 x-8 is divided by x^2+x-3 is

Options

  1. A3 x^2-7 x-21
  2. B3 x^3-7 x^2+21 x-45
  3. C3 x^4-7 x^3+21 x^2-45+114
  4. D114 x-143

Correct answer

B. 3 x^3-7 x^2+21 x-45

Step-by-step solution

aligned p(x) & =3 x^5-4 x^4+5 x^3-3 x^2+6 x-8 t(x)= & x^2+x-3 aligned By dividing p ( x ) by t ( x ) , the quotient is 3 x ^3-7 x ^2+21 x - 45 and remainder is 114 x -143 . So, p(x)= t (x) (3 x^3-7 x^2+21 x-45 )+114 x-143 Thus, quotient is 3 x^3-7 x^2+21 x-45

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