AP EAMCET202421 May 2024Morning ShiftMathematicsQuadratic EquationActual
Roots of the equation a(b-c) x^2+b(c-a) x+c(a-b)=0 are
Options
- Aa(b-c) c(a-b) , 1
- Bb(c-a) c(a-b) , 1
- Cc(a-b) a(b-c) , 1
- Dc(a-b) b(c-a) , 1
Correct answer
C. c(a-b) a(b-c) , 1
Step-by-step solution
a(b-c) x^2+b(c-a) x+c(a-b)=0x=1 satisfies his equation Product of roots = c(a-b) a(b-c) =1 = c(a-b) a(b-c) = other root Roots are c(a-b) a(b-c) and 1