AP EAMCET202318 May 2023Evening ShiftMathematicsQuadratic EquationActual
If cosec , and are the roots of cx ^2+ bx + a =0(b c 0) , then b^2 (b^2-4 a c )=
Options
- A-2 c^4
- B2 c^4
- C-c^4
- Dc ^4
Correct answer
D. c ^4
Step-by-step solution
cx ^2+ bx + a =0 Let = cosec & = + =- b c & = a c aligned & Now, ^2- ^2=( + )( - ) & cosec ^2 - ^2 =- b c ( + )^2-4 & 1=- b c b^2 c^2 - 4 a c & 1=- b c b^2-4 a c c^2 b^2-4 a c c^2 =- c b & b^2-4 a c c^2 = c^2 b^2 b^2 (b^2-4 a c )=c^4 aligned