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AP EAMCET202317 May 2023Evening ShiftMathematicsQuadratic EquationActual

If , and are the roots of the equation x^3-a^2+b x-c=0 then, ⁻²+ ⁻²+ ⁻²=

Options

  1. Ab^2-3 a c c^2
  2. Bb^2-a c c^2
  3. Cb ^2-2 ac c ^2
  4. Db^2-4 a c e^2

Correct answer

C. b ^2-2 ac c ^2

Step-by-step solution

Since , , are the roots of the equation aligned & x^3-a x^2+b x-c=0 & + + = a & + + = b & = c aligned Now, 1 ^2 + 1 ^2 + 1 ^2 = ^2 ^2+ ^2 ^2+ ^2 ^2 ^2 ^2 ^2 aligned & = ( + + )^2-2 ( + + ) ( )^2 & = b^2-2 c a c^2 aligned

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