AP EAMCET202316 May 2023Evening ShiftMathematicsQuadratic EquationActual
If a and b are the roots of the equation y ^2+ y +1=0 , then the value of a^4+b^4+a⁻¹ b⁻¹ is
Options
- A1
- B0
- C5
- D2
Correct answer
B. 0
Step-by-step solution
Given the equation y^2+y+1=0 aligned & Now, a^4+b^4+a⁻¹ b⁻¹=a^4+b^4+ 1 a b & = (a^2+b^2 )^2-2 a^2 b^2+ 1 1 & = ((a+b)^2-2 a b )^2-2 1+1 & = ((-1)^2-2 )^2-1=1-1=0 aligned