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AP EAMCET202315 May 2023Evening ShiftMathematicsQuadratic EquationActual

and are the roots of the equation x^2-a x+b=0 . If ^2+ ^2 and ^3+ ^3 are the roots of the equation Ax ^2+ Bx + C =0 , then C =

Options

  1. Aa^5-5 a^3 b+6 a b^2
  2. Ba^5+5 a^3 b-6 a b^2
  3. Ca^5-5 a^3 b-6 a b^2
  4. Da^5+5 a^3 b+6 a b^2

Correct answer

A. a^5-5 a^3 b+6 a b^2

Step-by-step solution

Since + =a, =b Now ^2+ ^2=( + )^2-2 =a^2-2 b ^3+ ^3=( + ) ( ^2+ ^2- )=a (a^2-3 b ) So, quadratic equation (x- (a^2-2 b ) (x- (a^3-3 a b ) ) . Thus constant term aligned & C= (a^2-2 b ) (a^3-3 a b ) & =a^5-5 a^3 b+6 a b^2 aligned

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