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AP EAMCET202315 May 2023Evening ShiftMathematicsQuadratic EquationActual

If -1 is a twice repeated root of the equation a x^3+b x^2+c x+1=0 , then

Options

  1. Ab =2 a +1, c = a +1
  2. Bb =2 a +1, c = a -2
  3. Cb =2 a +1, c = a +2
  4. Db=2 a-1, c=a+2

Correct answer

C. b =2 a +1, c = a +2

Step-by-step solution

Let roots of equation be -1,-1, Now, = -1 a and -1-1- 1 a = -b a b=2 a+1 and -a+b-c+1=0 c=-a+b+1 c=a+2

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