A person tries to broadcast with the same antenna both the signals at 10^7 ~Hz and 10^6 ~Hz . If the receiver at some distance has to receive an equal strength for both the frequencies, then the broadcaster has to approximately increase the signal strength at 10^6 ~Hz to 10^7 ~Hz by

Step-by-step solution

Power of signal radiated by an antenna P 1 ^2 , where, = wavelength of signal or P v^2 , where, v= frequency so P₁ P₂ = v₁^2 v₂^2 Given, v₁=10^7 ~Hz , v ₂=10^6 ~Hz aligned P₁ P₂ & = ( 10^7 10^6 )^2=100 P₁ & =100 P₂ aligned Power of frequency 10^7 is 100 times greater than 10^6 . So, signal strength of frequency 10^6 ~Hz need to be increased by 100 times for equal strength at some distance.