AP EAMCET202125 Aug 2021Morning ShiftMathematicsQuadratic EquationActual
Let m and n be two integers such that 0 m 10 and 0 n 10 . Then, the number of ordered pairs (m, n) such that x^2+m x+n=0 has real roots is
Options
- A71
- B73
- C75
- D72
Correct answer
B. 73
Step-by-step solution
Given, x^2+m x+n=0 has real roots. array ll m^2-4 n 0 0 m, n 10, m^2 4 n m=10, & n= 0,1,2, , 10 =11 m=9, & n= 0,1,2, , 10 =11 m=8, & n= 0,1,2, , 10 =11 m=7, & n= 0,1,2, , 10 =11 m=6, & n= 0,1,2, , 9 =10 m=5, & n= 0,1,2, , 6 =7 m=4, & n= 0,1,2,3,4 =5 m=3, & n= 0,1,2 =3 m=2, & n= 0,1 =2 m=1, & n= 0 =1 m=0, & n= 0 =1 array Number of order pair of (m, n) is 11+11+11+11+10+7+5+3+2+1+1=73