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AP EAMCET202022 Sep 2020Evening ShiftMathematicsQuadratic EquationActual

If the roots of the equation x^3-a x^2+b x-c=0 are in GP, then b^3 a^3

Options

  1. A1
  2. B–1
  3. Cc
  4. D-c

Correct answer

C. c

Step-by-step solution

aligned & Let roots be p r , p, p r & p r +P+p r=a & p^2 r +P^2 r+p^2=b aligned p^3=c Eq. (ii) Eq. (i) p^2 ( 1 r +r+1 ) p ( 1 r +r+1 ) = b a p= b a from Eq. (iii) ( b a )^3=c b^3 a^3 =c Hence, option (3) is correct.

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