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AP EAMCET202018 Sep 2020Evening ShiftMathematicsQuadratic EquationActual

If the roots of the given equation (( p-1) x^2+( p) x+ p=0 ) are real, then

Options

  1. A(p (- , 0) )
  2. B(p ( - 2 , 2 ) )
  3. C(p (0, ) )
  4. D(p (0,2 ) )

Correct answer

C. (p (0, ) )

Step-by-step solution

(( p-1) x^2+( p) x+ p=0 ) Since, roots are real ( array rlrl & 0 b^2-4 a c 0 & ( p)^2-4( p-1) ( p) 0 & ^2 p 0 and ( p-1) 0 P R & p 0 & p (0, ) array ) Hence, option (c) is correct.

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