TS EAMCET20215 Aug 2021Morning ShiftPhysicsMagnetic Effects of CurrentActual
Two capacitors, C 1 = 2 mF and C 2 = 8 mF are connected in series across a 300   V source. Then
Options
- AThe charge on each capacitor is 480 × 10 - 3   C
- BThe potential difference across C 1 is 60   V
- CThe potential difference across C 2 is 240   V
- DThe energy stored in the system is 5 . 2 × 10 - 2   J
Correct answer
A. The charge on each capacitor is 480 × 10 - 3   C
Step-by-step solution
The capacitors are connected in series then the net capacitance will be, C n e t = C 1 × C 2 C 1 + C 2 = 2 × 8 2 + 8 = 1 . 6   mF , then the net charge will be, Q n e t = C n e t V = 1 . 6 × 10 - 3 × 300 = 480 × 10 - 3   C , which will be same in each capacitor now potential difference across each capacitor will be, V 1 = Q n e t C 1 = 480 × 10 - 3   C 2 × 10 - 3 = 240   V and V 2 = Q n e t C 2 = 480 × 10 - 3   C 8 × 10 - 3 = 60   V and the