The magnetic field intensity ( H ) at the centre of a long solenoid carrying a current of 2   A , is found to be 1000   A . The number of turns per centimeter of the solenoid is ( Use μ 0 = 4 π × 10 - 7   T   m   A - 1 )

Step-by-step solution

The magnetic field at the centre of a long solenoid is given by in terms of magnetic permeability in free space, B = μ 0 n i                           . . . ( 1 ) . And magnetic intensity is given by H = B μ 0 ∴ H = n i , [using 1 ] ⇒ 1000 = n × 2 ⇒ n = 500   turns   meter - 1 ⇒ n = 5   turns   cm - 1