For a wire, as shown in the figure, carrying a current of 10 ~A , then the magnetic induction field at the point O is [talse, ₀=4 10⁻⁷ H / m ]

Step-by-step solution

Magnetic field due to a Iong current carrying wire at one end is given by B= ₀ i 4 d . (where, i= current and d= distance from the wire) For both the wire, i=10 ~A , d= 1 2 10⁻² ~m Magnetic field due to one wire, gathered B= ₀ 10 4 ( 1 2 10⁻² ) B= 2 10⁻⁷ 10 10⁻² =2 10⁻⁴ ~T gathered Due to both wires magnetic field is in same direction, so they will add up. Total magnetic field, B=2 (2 10⁻⁴ ) B=4 10⁻⁴ ~T