AP EAMCET201920 Apr 2019Evening ShiftMathematicsQuadratic EquationActual
If , , are the roots of the equation x^3-a x^2+b x-c=0 , then ^2( + )=
Options
- Aa b-3 c
- Ba b-3 c c
- Cb^2-2 a c c^2
- Da^2-2 b c^2
Correct answer
A. a b-3 c
Step-by-step solution
If , , are the roots of the equation. x^3-a x^2+b x-c=0 Then, + + =a, + + =b and =c . Now, ^2( + )= ^2(a- ) [as + + =a] aligned & =a ^2- ^3 & =a [( + + )^2-2( + + ) ]-[( + + ) & . ( ^2+ ^2+ ^2- - - )+3 ] & =a [( + + )^2-2( + + ) ]-( + + ) & ( + + )^2-3( + + )+3 ] & =a [a^2-2 b ]- [a a^2-3 b +3 c ] & =a^3-2 a b-a^3+3 a b-3 c=a b-3 c aligned Hence, option (a) is correct.