AP EAMCET201823 Apr 2018Morning ShiftMathematicsQuadratic EquationActual
If a, b and c are the roots of x^3+4 x+1=0 , then 1 a+b + 1 b+c + 1 c+a =
Options
- A2
- B3
- C4
- D-4
Correct answer
C. 4
Step-by-step solution
a, b, c are roots of x^3+4 x+1=0 aligned & x^3+0 x^2+4 x+1=0 So, & a+b+c=0 a b c=-1 aligned and a b+b c+c a=4 Now, 1 a+b + 1 b+c + 1 c+a = 1 -c + 1 -a + 1 -b =- ( 1 a + 1 b + 1 c )=- ( b c+a c+a b a b c )=- ( 4 -1 )=4