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AP EAMCET2012MathematicsQuadratic Equation

In P Q R, R= 4 , ( P 3 ), ( Q 3 ) are the roots of the equation a x^2+b x+c=0 , then

Options

  1. Aa+b=c
  2. Bb+c=0
  3. Ca+c=0
  4. Db=c

Correct answer

A. a+b=c

Step-by-step solution

Given, R= 4 Also, P+Q+R= array ll & P+Q+ 4 = & P+Q= 3 4 & P 3 + Q 3 = 4 & ( P 3 + Q 3 )= ( 4 ) & P 3 + Q 3 1- P 3 Q 3 =1 array Since, P 3 and Q 3 are the roots of the equation a x^2+b x+c=0 . P 3 + Q 3 =- b a and P 3 Q 3 = c a From Eq. (i), - b a 1- c a =1 array ll & -b a-c =1 & a+b=c array

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