NEETChemistrySurface Chemistry
Match List - I with List - II . ( array |l|l|l|l| & List-I & & List-II & (Colloid Preparation Method) & & (Chemical Reaction) (a) & Hydrolysis & (i) & aligned & 2 AuCl ₃+3 HCHO +3 H ₂ O & 2 Au ( sol )+3 HCOOH +6 HCl aligned (b) & Reduction & (ii) & As ₂ O ₃+3 H ₂ ~S As ₂ ~S ₃( sol )+3 H ₂ O (c) & Oxidation & (iiI) & SO ₂+2 H ₂ ~S 3 ~S ( sol )+2 H ₂ O (d) & Double Decomposition & (iv) & FeCl ₃+3 H ₂ O Fe ( OH )₃( sol
Options
- A( a ) - ( i ) , ( b ) - ( iii ) , ( c ) - ( ii ) , ( d ) - ( iv )
- B( a ) - ( iv ) , ( b ) - ( i ) , ( c ) - ( iii ) , ( d ) - ( ii )
- C( a ) - ( i ) , ( b ) - ( ii ) , ( c ) - ( iv ) , ( d ) - ( iii )
- D( a ) - ( iv ) , ( b ) - ( ii ) , ( c ) - ( iii ) , ( d ) - ( i )
Correct answer
B. ( a ) - ( iv ) , ( b ) - ( i ) , ( c ) - ( iii ) , ( d ) - ( ii )
Step-by-step solution
Colloid preparation by Hydrolysis reaction: (no change in oxidation number.) FeCl 3 + 3 H 2 O → Fe ( OH ) 3 ( sol ) + 3 HCl Gold sol is prepared by reduction reaction: 2 AuCl 3 + 3 HCHO + 3 H 2 O → 2 Au ( sol ) + 3 HCOOH + 6 HCl Preparation of sulphur sol:(oxidation) SO 2 + 2 H 2 S → 3 S ( sol ) + 2 H 2 O Preparation of colloid by double decomposition reaction: As 2 O 3 + 3 H 2 S → As 2 S 3 ( sol ) + 3 H 2 O