AP EAMCET202420 May 2024Morning ShiftMathematicsSequences and SeriesActual
1 3.7 + 1 7.11 + 1 11.15 + to 50 terms =
Options
- A50 203
- B50 609
- C150 203
- D25 609
Correct answer
B. 50 609
Step-by-step solution
1 3.7 + 1 7.11 + 1 11.15 + _n= 1 (4 n-1)(4 n+3) = 1 4 [ 1 4 n-1 - 1 4 n+3 ]T₁= 1 4 [ 1 3 - 1 7 ] T₂= 1 4 [ 1 7 - 1 11 ]T_ n-1 = 1 4 [ 1 4 n-5 - 1 4 n-1 ] S _ n = T ₁+ T ₂+ + T _ n = 1 4 [ 1 3 - 1 4 n+3 ]S_n= n 3(4 n+3) S₅₀= 50 3(200+3) = 50 609