AP EAMCET202420 May 2024Morning ShiftMathematicsSequences and SeriesActual
1+ 1 3 + 1.3 3.6 + 1.3 .5 3.6 .9 + to =
Options
- A5
- B6
- C15
- D3
Correct answer
D. 3
Step-by-step solution
1+ 1 3 + 1.3 3.6 + 1.3 .5 3.6 .9 + to Let S=1+ 1 3(1)! + 1.3 (3)^2(2!) + 1.3 .5 (3)^3(3!) + Comparing (1-x)^ - m n =1+ m n x+ m(m+n) 2! ( x n )^2+ m(m+n)(m+2 n) 3! ( x n )^3+ =1, n=2 & x= 2 3 S=(1-x)^ - m n = (1- 2 3 )^ - 1 2 = 3