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AP EAMCET202420 May 2024Morning ShiftMathematicsSequences and SeriesActual

1+ 1 3 + 1.3 3.6 + 1.3 .5 3.6 .9 + to =

Options

  1. A5
  2. B6
  3. C15
  4. D3

Correct answer

D. 3

Step-by-step solution

1+ 1 3 + 1.3 3.6 + 1.3 .5 3.6 .9 + to Let S=1+ 1 3(1)! + 1.3 (3)^2(2!) + 1.3 .5 (3)^3(3!) + Comparing (1-x)^ - m n =1+ m n x+ m(m+n) 2! ( x n )^2+ m(m+n)(m+2 n) 3! ( x n )^3+ =1, n=2 & x= 2 3 S=(1-x)^ - m n = (1- 2 3 )^ - 1 2 = 3

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