Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
AP EAMCET201921 Apr 2019Morning ShiftMathematicsStatisticsActual

For a data consisting of 15 observations x_i , i=1,2,3, , 15 the following results are obtained : _ i=1 ¹⁵ x_i=170 ; _ i=1 ¹⁵ x_i^2=2830 . If one of the observation namely 20 was found wrong and was replaced by its correct value 30 , then the corrected variance is

Options

  1. A80
  2. B78
  3. C76
  4. D75

Correct answer

B. 78

Step-by-step solution

Given, x^2=2830 and x=170 Increase in x=10 and increase in x^2=(30)^2-(20)^2 aligned & =900-400=500 & x^ =170+10=180 & and x^ 2 =2830+500=3330 & We know that, variance = x^2 n - ( x n )^2 & = 3330 15 - ( 180 15 )^2 [here, n=15 ] & =222-144=78 aligned

Practice Statistics on Quantrex Academy →

More from Statistics

The variance of a set of 20 observations is 16. If 7 is added to each observation, and then 5 is subtracted from each resulting observation, what will be the new standard deviation 2026If for a distribution of 20 items, (x - 4) = 10 and (x - 4)^2 = 85 then the standard deviation is: 2026Consider the data of scores obtained by students in an examination. If the score of every student is increased by 2 marks, then which of the following statements is TRUE? 2026The mean and standard deviation of 100 items are 50 and 4 , respectively then the sum of all squares of the items is 2026If _ i=1 ^9 (x_i-5 )=9 and _ i=1 ^9 (x_i-5 )^2=45 , then the standard deviation of the nine observations x ₁, x ₂, , x ₉ is 2025Variance of the following continuous frequency distribution is Class Interval 0 – 4 4 – 8 8 – 12 12 – 16 Frequency 1 2 2 1 2025The mean deviation from the median for the following data is x_i 9 3 7 2 5 f_i 1 6 2 8 4 2025The mean deviation about the mean for the following data is Class Interval 0 – 2 2 – 4 4 – 6 6 – 8 8 – 10 Frequency 1 3 4 1 2 2025 Full Statistics list All AP EAMCET PYQs