If the variance of the distribution array cccccccc x _ i & 4 & 8 & 11 & 17 & 20 & 24 & 32 f _ i & 3 & 5 & 9 & 5 & 4 & 3 & 1 array is 45.8 , then the variance of the distribution. array llllllll x _ i & 10 & 18 & 24 & 36 & 42 & 50 & 66 f _ i & 3 & 5 & 9 & 5 & 4 & 3 & 1 array

Step-by-step solution

Mean of given observation (x_i ) is array r (4 3)+(8 5)+(11 9)+(17 5)+(20 4) +(24 3)+(32 1) = 420 30 =14 array So, aligned ce & =k 10^2+6^2+3^2+3^2+6^2+10^2+18^2 30 & =45.8 (given) aligned Now, mean of given observation (y_i ) is array r array r (10 3)+(18 5)+(24 9)+(36 5)+(42 4) +(50 3)+(66 1) array aligned 30 & 900 30 =30 aligned array So, variance aligned & =k 20^2+12^2+6^2+6^2+12^2+20^2+36^2 30 & =4 k ( 10^2+6^2+3^2+3^2+6^2+10^2+18^2 30 ) & =4 45.8=183.2 aligned