AP EAMCET202422 May 2024Morning ShiftMathematicsStraight LinesActual

The equation of the locus of points which are equidistant from the points (2,3) and (4,5) is

Options

Ax+y=0
Bx+y=7
C4 x+4 y=38
Dx+y=1

Correct answer

B. x+y=7

Step-by-step solution

aligned & Let P(x, y) be equidistance from A(2,3) and B(4,5) & (P A)^2=(P B)^2 & (x-2)^2+(y-3)^2=(x-4)^2+(y-5)^2 & & x^2-4 x+4+y^2+9-6 y=x^2+16-8 x+y^2+25-10 y & 4 x+4 y=28 x+y=7 aligned

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