AP EAMCET202318 May 2023Morning ShiftMathematicsStraight LinesActual
The equation of the line, passing through the point (a ^3 , a ^3 ) and perpendicular to the line x -y =a , is
Options
- A2 x +2 y =a 2
- Bx -y =a 2
- Cx +y =a 2
- Dx -y =a 2
Correct answer
A. 2 x +2 y =a 2
Step-by-step solution
Slope of line x - y = a is m ^ = So, the slope of the required line is: m= -1 m^ =- Now, the required equation of line is: (y-a ^3 )=m (x-a ^3 ) aligned & y-a ^3 =- (x-a ^3 ) & y-a ^3 =-x +a ^3 & y+x =a ^3 +a ^2 & y+x =a ( ^2 + ^2 ) & y +x =a & 2 x +2 y =a 2 aligned