AP EAMCET202317 May 2023Evening ShiftMathematicsStraight LinesActual
The lines L₁: y-x=0 and L₂: 2 x+y=0 intersect the line L₃: y+2=0 at P and Q respectively. The bisector of the acute angle between L ₁ and L ₂ intersects L ₃ at R . Statement 1: PR : RQ =2 2 : 5 Statement 2: In any triangle, the bisector of an angle divides the triangle into two similar triangles.
Options
- AStatement-1 is true, Statement-2 is false
- BStatement-1 is false, Statement- 2 is true
- CStatement-1 and Statement-2 are both true
- DStatement-1 and Statement- 2 are both false
Correct answer
A. Statement-1 is true, Statement-2 is false
Step-by-step solution
Given: L ₁: y-x=0 aligned & L ₂: 2 x+y=0 & ~L ₃=y+2=0 aligned Solving L ₁ and L ₃ , we get x=-2, y=-2 p(x, y)=(-2,-2) Solving L ₂: 2 x+y=0 & ~L ₃: y+2=0 , we get x=1 & y=-2 Q(x, y)=(1,-2) Now, OP = (0-(-2))^2+(0-(-2))^2 =2 2 OR = (0-1)^2+(0-(-2))^2 = 5 OR is the bisector of POQ , therefore R divided in the same ratio as O P : OQ. Thus, PR : RQ = AP : AQ =2 2 : 5 Statement-1 is true. Statement-2 is clearly false.